Lecture 21 — Isostasy & Lithospheric Flexure

ESS 314 — Introduction to Geophysics
University of Washington · Spring 2026

Marine Denolle · Wed May 6, 2026 · JHN 111

By the end of this lecture, you should be able to…

  • [LO-21.1] Apply Archimedes — compute crustal-root thickness (Airy) and column density (Pratt).
  • [LO-21.2] Distinguish local (Airy/Pratt) vs. regional (flexural) compensation.
  • [LO-21.3] Interpret a Bouguer profile as evidence for compensation; describe the isostatic-residual.
  • [LO-21.4] Estimate post-glacial rebound timescale and connect to mantle viscosity.
  • [LO-21.5] Use the flexural parameter α\alpha to predict forebulge wavelength.

Course objectives addressed: LO-1, LO-2, LO-3, LO-4.

A puzzle from Lecture 19

The Bouguer anomaly over a mountain range is broadly negative, not positive.

→ The mountain is not an uncompensated excess mass.

Beneath every large topographic feature there is a mass deficit at depth — a root of light material — that almost exactly balances the topographic excess.

The mountain is floating.

Archimedes for mountains

Hydrostatic equilibrium at the depth of compensation:

∫ρcolumn,1 g dz  =  ∫ρcolumn,2 g dz\int \rho_{\text{column,1}} \, g \, dz \;=\; \int \rho_{\text{column,2}} \, g \, dz

Below the depth of compensation, the asthenosphere flows freely on geological timescales.
Any pressure imbalance there drives lateral flow that restores equilibrium.

→ Two end-member ways to satisfy this: Airy and Pratt.

Airy and Pratt — two end-member compensation styles

Airy and Pratt isostasy compared

  • Airy: same density, variable thickness. High mountain → deep root.
  • Pratt: same depth, variable density. High mountain → low-density column.

Both satisfy hydrostatic equilibrium but make different deep-Earth predictions.

Airy — the root formula

ρch=(ρm−ρc)r⇒r=ρcρm−ρc h\rho_{c} h = (\rho_{m} - \rho_{c}) r \quad\Rightarrow\quad r = \frac{\rho_{c}}{\rho_{m}-\rho_{c}} \, h

For ρc=2700\rho_{c} = 2700, ρm=3300\rho_{m} = 3300 kg m⁻³:

r/h=4.5r/h = 4.5

A 1-km mountain → 4.5-km root.

The Tibetan Plateau (h≈5h \approx 5 km, Moho ≈70\approx 70 km) is approximately Airy.

Pratt — the density formula

ρcHref=ρblock(Href+h)⇒ρblock=ρc HrefHref+h\rho_{c} H_{\text{ref}} = \rho_{\text{block}} (H_{\text{ref}} + h) \quad\Rightarrow\quad \rho_{\text{block}} = \rho_{c} \, \frac{H_{\text{ref}}}{H_{\text{ref}} + h}

For Href=35H_{\text{ref}} = 35 km, h=5h = 5 km: ρblock=0.875 ρc≈2362\rho_{\text{block}} = 0.875\,\rho_{c} \approx 2362 kg m⁻³ (12% lower).

Mid-ocean-ridge crests, hot spots, and oceanic plateaus are approximately Pratt.

Real Earth: a mixture

Neither model is solely correct. Earth applies both.

  • Airy dominates large-scale crustal features (continents, plateaus).
  • Pratt-type density variations dominate at the oceanic-continental boundary and near hot spots.

→ The choice is a scale and setting question.

The isostatic-residual anomaly

Δgiso=ΔgBouguer−Δgcompensation prediction\Delta g_{\text{iso}} = \Delta g_{\text{Bouguer}} - \Delta g_{\text{compensation prediction}}

  • Zero residual → load is fully compensated.
  • Positive residual → uncompensated excess mass; load supported elastically (e.g. recent volcano).
  • Negative residual → uncompensated deficit; load not yet equilibrated (e.g. active glacier).

Transient residuals are diagnostic of active geodynamic processes.

Time-dependent compensation — post-glacial rebound

Post-glacial rebound

Ice sheet removed → lithosphere rebounds toward equilibrium.
Rate set by mantle viscosity:

τ∼4πηρmgL\tau \sim \frac{4\pi\eta}{\rho_{m} g L}

For Fennoscandia (L∼1000L \sim 1000 km, η∼1021\eta \sim 10^{21} Pa s): τ≈4 ⁣− ⁣5\tau \approx 4\!-\!5 ka — uplift continues at ~9 mm/yr today.

Inverse problem: get viscosity from rebound

Two pieces of data:

  • Total post-glacial uplift (Fennoscandia: ∼300\sim 300 m).
  • Present-day uplift rate (∼9\sim 9 mm/yr).

→ Ratio gives τ\tau → equation gives η\eta.

This single inverse problem has driven mantle-viscosity research for 50 years (Whitehouse 2018 review, CC BY 4.0, https://doi.org/10.5194/esurf-6-401-2018).

Beyond local compensation — flexure

Real lithosphere has elastic strength. A vertical load at one point produces regional deformation that extends 100s of km.

The thin-plate equation:

D d4wdx4  +  (ρm−ρw) g w  =  q(x)D \, \frac{d^{4}w}{dx^{4}} \;+\; (\rho_{m}-\rho_{w}) \, g \, w \;=\; q(x)

with flexural rigidity D=ETe3/[12(1−ν2)]D = E T_{e}^{3} / [12(1-\nu^{2})]
and flexural parameter α=[4D/(ρm ⁣− ⁣ρw)g]1/4\alpha = \bigl[ 4D / (\rho_{m}\!-\!\rho_{w}) g \bigr]^{1/4}.

What flexure looks like

Lithospheric flexure under a line load

Load → central depression + forebulge at x≈παx \approx \pi\alpha + zero crossing.
Increasing TeT_{e} widens and reduces the deflection.
Inverting the observed forebulge geometry → estimates TeT_{e}.

When does each model apply?

Feature Width Compensation
Continent / plateau ≫α\gg \alpha Local (Airy)
Mountain range ∼\sim a few α\alpha Mixed
Single seamount ≪α\ll \alpha Regional (flexural)
Subduction trench bend in plate Flexural

A continental craton has Te≈80T_{e} \approx 80 km; an oceanic spreading centre has TeT_{e} near zero.

Worked example — Mount Olympus (PNW)

Olympic Mountains: h≈2.4h \approx 2.4 km. Treat as Airy-compensated.

Predicted root: r=(ρc/(ρm−ρc)) h=4.5×2.4=10.8r = (\rho_{c}/(\rho_{m}-\rho_{c}))\, h = 4.5 \times 2.4 = 10.8 km.
Predicted Bouguer (slab approx of root):

Δgroot≈−2πG(ρm−ρc)r≈−272 mGal\Delta g_{\text{root}} \approx -2\pi G (\rho_{m}-\rho_{c}) r \approx -272 \text{ mGal}

Free-air anomaly should remain small (<50<50 mGal) — root and topography roughly cancel.

→ The Olympics sit on the Cascadia accretionary prism — active loading. The isostatic residual is the signal of that active process.

Course connections

  • Backward: L19 (Bouguer construction) and L20 (regional vs residual).
  • Forward: L22 — rheological structure of the lithosphere; viscoelasticity.
  • Forward: Module 7 — dynamic topography, vertical motion driven by mantle convection.
  • Cross-link: present-day GIA is a key correction to GPS-measured vertical land motion → tide gauges → sea-level reconstruction.

Research horizon

  • Whitehouse (2018) — GIA modelling review (CC BY 4.0). Key open question: depth profile of mantle viscosity.
  • Forte & Rowley (2022) — much of long-wavelength Bouguer / geoid is dynamic topography, not local isostasy.
  • Antarctic / Greenland mass balance — disentangling present-day ice loss from underlying GIA is the largest single uncertainty in 21st-century sea-level projections.

Societal — Cascadia subsidence and the tide gauge

PNW tide gauges show slower sea-level rise than the global mean.

This is not measurement error — it is inter-seismic uplift from Cascadia locking.

In the next M9 megathrust event:

  • Coastal Washington will drop 0.5–2 m in minutes.
  • Tide-gauge baseline resets.
  • Locally, "sea level" is redefined.

→ Vertical land motion (this lecture's mechanics, on a transient timescale) directly informs Cascadia hazard.

USGS Cascadia resource (public domain): https://www.usgs.gov/programs/earthquake-hazards/science/cascadia-subduction-zone

AI Literacy — Prompt Lab

Three prompts that test whether AI handles this lecture's reasoning.

P1. Compare Airy and Pratt for the Tibetan Plateau. Which fits observations and why?
→ Good: derives both, computes amplitudes, notes empirical mixture. Poor: qualitative-only.

P2. Estimate mantle viscosity from Fennoscandian uplift (9 mm/yr; total 300 m).
→ Good: τ≈33\tau \approx 33 ka → η≈1021\eta \approx 10^{21} Pa s. Common error: confuses rebound amplitude with load amplitude.

P3. Why do oceanic seamounts produce forebulges but individual continental peaks rarely do?
→ Good: invokes TeT_{e} contrast and notes that continental peaks usually sit within larger compensating structures. Either side alone is incomplete.

Concept Check

  1. Two ranges of identical surface elevation produce Bouguer anomalies of −100-100 mGal and −200-200 mGal. Which is more nearly locally compensated, and what does the difference suggest about lithospheric strength?
  2. A continental margin shows a forebulge 250 km offshore of a deltaic load. With ρm−ρw=2270\rho_{m}-\rho_{w} = 2270 kg m⁻³, E=70E = 70 GPa, ν=0.25\nu = 0.25 — estimate TeT_{e}.
  3. Fennoscandia: ∼9\sim 9 mm yr⁻¹ uplift, total ∼300\sim 300 m post-glacial. Estimate τ\tau and η\eta. Are they in the canonical range?